3q^2-20q+12=0

Solution for 3q^2-20q+12=0 equation:

Simplifying
3q2 + -20q + 12 = 0

Reorder the terms:
12 + -20q + 3q2 = 0

Solving
12 + -20q + 3q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(2 + -3q)(6 + -1q) = 0

Subproblem 1
Set the factor '(2 + -3q)' equal to zero and attempt to solve:

Simplifying
2 + -3q = 0

Solving
2 + -3q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3q = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -3q = 0 + -2
-3q = 0 + -2

Combine like terms: 0 + -2 = -2
-3q = -2

Divide each side by '-3'.
q = 0.6666666667

Simplifying
q = 0.6666666667
Subproblem 2
Set the factor '(6 + -1q)' equal to zero and attempt to solve:

Simplifying
6 + -1q = 0

Solving
6 + -1q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1q = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1q = 0 + -6
-1q = 0 + -6

Combine like terms: 0 + -6 = -6
-1q = -6

Divide each side by '-1'.
q = 6

Simplifying
q = 6
Solution
q = {0.6666666667, 6}